1/2y^2-5/2y-12

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Solution for 1/2y^2-5/2y-12 equation: 


y in (-oo:+oo)

(1/2)*y^2-((5/2)*y)-12 = 0

(1/2)*y^2+(-5/2)*y-12 = 0

1/2*y^2-5/2*y-12 = 0

DELTA = (-5/2)^2-(-12*1/2*4)

DELTA = 121/4

DELTA > 0

y = ((121/4)^(1/2)+5/2)/(1/2*2) or y = (5/2-(121/4)^(1/2))/(1/2*2)

y = 8 or y = -3

y in { -3, 8 }

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